# Riddle

**URL:** <https://forum.fudiabetes.org/t/riddle/2717>\
**Category:** Fun\
**Created:** [November 27, 2017, 7:44pm UTC](https://forum.fudiabetes.org/t/riddle/2717 "2017-11-27T19:44:08Z")\
**Posts on this page:** 20\
**Page:** 1

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**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 7:44pm UTC](https://forum.fudiabetes.org/t/riddle/2717/1 "2017-11-27T19:44:08Z")

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![IMG_0825](https://canada1.discourse-cdn.com/flex030/uploads/fudiabetes/original/2X/1/1387cca205e230ea3f80001b32cd8068fd43627f.JPG)

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**Author:** ![Chris](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/chris/32/382_2.png) [@Chris](https://forum.fudiabetes.org/u/Chris)\
**Post date:** [November 27, 2017, 8:21pm UTC](https://forum.fudiabetes.org/t/riddle/2717/2 "2017-11-27T20:21:41Z")

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69 would be my answer.

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**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 8:26pm UTC](https://forum.fudiabetes.org/t/riddle/2717/3 "2017-11-27T20:26:41Z")

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I have a different answer. Pretty sure mine is right because the third time was the charm…

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**Author:** ![dm61](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/dm61/32/1602_2.png) [@dm61](https://forum.fudiabetes.org/u/dm61)\
**Post date:** [November 27, 2017, 8:32pm UTC](https://forum.fudiabetes.org/t/riddle/2717/4 "2017-11-27T20:32:54Z")

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38 😉

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**Author:** ![Boerenkool](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/boerenkool/32/6307_2.png) [@Boerenkool](https://forum.fudiabetes.org/u/Boerenkool)\
**Post date:** [November 27, 2017, 8:35pm UTC](https://forum.fudiabetes.org/t/riddle/2717/5 "2017-11-27T20:35:52Z")

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> [@dm61](#):
>
> 38 😉

That’s my answer too

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**Author:** ![Beacher](https://avatars.discourse-cdn.com/v4/letter/b/a6a055/32.png) [@Beacher](https://forum.fudiabetes.org/u/Beacher)\
**Post date:** [November 27, 2017, 8:41pm UTC](https://forum.fudiabetes.org/t/riddle/2717/6 "2017-11-27T20:41:46Z")

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> [@Boerenkool](#):
>
> That’s my answer too

And mine.

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**Author:** ![Aaron](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/aaron/32/1454_2.png) [@Aaron](https://forum.fudiabetes.org/u/Aaron)\
**Post date:** [November 27, 2017, 8:49pm UTC](https://forum.fudiabetes.org/t/riddle/2717/7 "2017-11-27T20:49:51Z")

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I get 38 too.

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**Author:** ![CarolynA](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/carolyna/32/1828_2.png) [@CarolynA](https://forum.fudiabetes.org/u/CarolynA)\
**Post date:** [November 27, 2017, 9:02pm UTC](https://forum.fudiabetes.org/t/riddle/2717/8 "2017-11-27T21:02:25Z")

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I got 67

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**Author:** ![bkh](https://avatars.discourse-cdn.com/v4/letter/b/da6949/32.png) [@bkh](https://forum.fudiabetes.org/u/bkh)\
**Post date:** [November 27, 2017, 9:23pm UTC](https://forum.fudiabetes.org/t/riddle/2717/9 "2017-11-27T21:23:12Z")

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I’m with CarolynA on 67

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<div class="post-metadata">

**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 9:24pm UTC](https://forum.fudiabetes.org/t/riddle/2717/10 "2017-11-27T21:24:24Z")

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67 is a prime number… how could the answer possibly be 67?

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**Author:** ![Pianoplayer7008](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/pianoplayer7008/32/1507_2.png) [@Pianoplayer7008](https://forum.fudiabetes.org/u/Pianoplayer7008)\
**Post date:** [November 27, 2017, 9:28pm UTC](https://forum.fudiabetes.org/t/riddle/2717/11 "2017-11-27T21:28:31Z")

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I got 67 as well…

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<div class="post-metadata">

**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 9:28pm UTC](https://forum.fudiabetes.org/t/riddle/2717/12 "2017-11-27T21:28:42Z")

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Explain?

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<div class="post-metadata">

**Author:** ![Pianoplayer7008](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/pianoplayer7008/32/1507_2.png) [@Pianoplayer7008](https://forum.fudiabetes.org/u/Pianoplayer7008)\
**Post date:** [November 27, 2017, 9:30pm UTC](https://forum.fudiabetes.org/t/riddle/2717/13 "2017-11-27T21:30:24Z")

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15 + 15 + 15 = 45

4 + 4 + 15 = 23

4 + 3 + 3 = 10

3 + 4 + (4 x 15) = 67

What did you get?

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<div class="post-metadata">

**Author:** ![MM2](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/mm2/32/3032_2.png) [@MM2](https://forum.fudiabetes.org/u/MM2)\
**Post date:** [November 27, 2017, 9:55pm UTC](https://forum.fudiabetes.org/t/riddle/2717/15 "2017-11-27T21:55:15Z")

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I think 67 too.

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**Author:** ![Eric](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/eric/32/9209_2.png) [@Eric](https://forum.fudiabetes.org/u/Eric)\
**Post date:** [November 27, 2017, 9:57pm UTC](https://forum.fudiabetes.org/t/riddle/2717/16 "2017-11-27T21:57:22Z")

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The symbols are not the same in all the equations.

If the 3 o’clock clock is 3, then the 2 o’clock clock shown in the last equation is probably 2 (but only if we assume it is a linear clock, so you would have to discount String theory, M theory, and Itzhak Bars’ theory of time having two separate dimensions).

The bananas are also not the same. If the bunch of 4 bananas is 4, then the bunch of 3 bananas is 3.

And hexagon / pentagon / rectangle shape is also not the same in each equation.

This shape is certainly 15:  
 ![image](https://canada1.discourse-cdn.com/flex030/uploads/fudiabetes/original/2X/3/31581ff9817b3440d51631d8d1069e814772734b.jpg)

But assuming this shape is 11 simply by counting sides is not something that can be proven with given information.  
 ![image](https://canada1.discourse-cdn.com/flex030/uploads/fudiabetes/original/2X/d/d0a553d3646b3daeb8328cbb9ef5f116382e8f38.jpg)

Just because a hexagon / pentagon / rectangle is 15 (6 sided figure, 5 sided figure, and 4 sided figure), does not guarantee a hexagon / pentagon is 11 (6 sided figure, 5 sided figure). The shapes could be exponential representations for all we know.

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<div class="post-metadata">

**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 9:59pm UTC](https://forum.fudiabetes.org/t/riddle/2717/17 "2017-11-27T21:59:32Z")

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> [@Eric](#):
>
> The shapes could be exponential representations for all we know.

There are 15 points in the first shape. There are 11 points in the final one. I think that’s just as sound as counting the bananas.

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<div class="post-metadata">

**Author:** ![Eric](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/eric/32/9209_2.png) [@Eric](https://forum.fudiabetes.org/u/Eric)\
**Post date:** [November 27, 2017, 10:02pm UTC](https://forum.fudiabetes.org/t/riddle/2717/18 "2017-11-27T22:02:25Z")

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38 is simply one possible solution, and easily accepted because it is the easiest to compute.

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<div class="post-metadata">

**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 10:05pm UTC](https://forum.fudiabetes.org/t/riddle/2717/19 "2017-11-27T22:05:02Z")

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It’s the answer that makes the most sense, unless you subscribe to the all clocks are worth 3, any bunch of bananas are worth 4, and all polygons are worth 15 theory. Or string theory, whatever that means…

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<div class="post-metadata">

**Author:** ![Eric](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/eric/32/9209_2.png) [@Eric](https://forum.fudiabetes.org/u/Eric)\
**Post date:** [November 27, 2017, 10:23pm UTC](https://forum.fudiabetes.org/t/riddle/2717/20 "2017-11-27T22:23:33Z")

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A hexagon/pentagon/rectangle is 15, sure. But that doesn’t mean a hexagon/pentagon is 11.

You can cut an 8 in half to make it look like a 3, but that doesn’t mean 1/2 of 8 is 3.  
 ![image](https://canada1.discourse-cdn.com/flex030/uploads/fudiabetes/original/2X/3/37673b0dd6bb90f73bd59e831bd670d69bde6d59.png)

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<div class="post-metadata">

**Author:** ![Sam](https://yyz2.discourse-cdn.com/flex030/user_avatar/forum.fudiabetes.org/sam/32/10595_2.png) [@Sam](https://forum.fudiabetes.org/u/Sam)\
**Post date:** [November 27, 2017, 10:25pm UTC](https://forum.fudiabetes.org/t/riddle/2717/21 "2017-11-27T22:25:45Z")

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Well you can cut the bananas in half too. It is the only reasonable assumption. I applaud your creativity though.

[Next page](https://forum.fudiabetes.org/t/riddle/2717.md?page=2)
